Better Practice When Working With Files

random0munky · 07-31-2012, 09:32 PM

Hey,

I have a question that I ran into when working with files on my linux box. I went ahead and pasted what I have in terminal.

MacBookPro:Test random0munky$ ls -l
total 0
-rw-r--r-- 1 random0munky staff 0 Jul 31 19:31 myTest
-rw-r--r-- 1 random0munky staff 0 Jul 31 19:31 myTest.new
MacBookPro:Test random0munky$ mv myTest myTest.orig
MacBookPro:Test random0munky$ mv myTest.new myTest
MacBookPro:Test random0munky$ ls -l
total 0
-rw-r--r-- 1 random0munky staff 0 Jul 31 19:31 myTest
-rw-r--r-- 1 random0munky staff 0 Jul 31 19:31 myTest.orig
MacBookPro:Test random0munky$

I feel there's a better way / using better practices to accomplish the same task. What do you guys think?

Edit: I noticed that when you do the mv command, that the permissions as well as the group doesn't update with the file. Now just need to see about how to go about updating those 2 values.

evo2 · 07-31-2012, 09:56 PM

Hi,

how about

Code:

mv -b -S '.orig' myTest.new myTest

If you do this often and also want to preserve the perms I would suggest a little shell script, shell function or alias.

Evo2.

random0munky · 07-31-2012, 10:02 PM

Quote:

Originally Posted by evo2

Hi,

how about

Code:

mv -b -S '.orig' myTest.new myTest

If you do this often and also want to preserve the perms I would suggest a little shell script, shell function or alias.

Evo2.

I can see where you're going with this. Unfortunately, the permissions didn't transfer =/

Edit: How about this: mv -b -S '.orig' myTest.new myTest | chmod --reference myTest.orig myTest

evo2 · 07-31-2012, 10:57 PM

Hi,

Quote:

Originally Posted by random0munky

Edit: How about this: mv -b -S '.orig' myTest.new myTest | chmod --reference myTest.orig myTest

Sure. You could put the following in your .bashrc

Code:

mvbk () {
mv -b -S '.orig' $1 $2 && chmod --reference $2.orig $2 
}

Then you just need to call

Code:

mvbk myTest.new myTest

You could also modify the function so that you it only needs one argument assuming that the you will always be wanting to move $1.new to $1
eg

Code:

mvbk () { 
mv -b -S '.orig' $1.new $1 && chmod --reference $1.orig $1
}

Then you could just call

Code:

mvbk myTest

Evo2.

random0munky · 07-31-2012, 11:02 PM

Quote:

Originally Posted by evo2

Hi,

Sure. You could put the following in your .bashrc

Code:

mvbk () {
mv -b -S '.orig' $1 $2 && chmod --reference $2.orig $2 
}

Then you just need to call

Code:

mvbk myTest.new myTest

You could also modify the function so that you it only needs one argument assuming that the you will always be wanting to move $1.new to $1
eg

Code:

mvbk () { 
mv -b -S '.orig' $1.new $1 && chmod --reference $1.orig $1
}

Then you could just call

Code:

mvbk myTest

Evo2.

Is there any other way that's a bit more prettier than the solutions we have came up with >.<

evo2 · 07-31-2012, 11:17 PM

Hi,

Quote:

Originally Posted by random0munky

Is there any other way that's a bit more prettier than the solutions we have came up with >.<

Hmm. Don't know. I like little shell functions.

Cheers,

Nick.