bash scripting question

brian0918 · 06-26-2003, 03:55 PM

I need to look for files of a certain name (such as: bleh*.*) within a directory and its subdirectories, and if any files have that sort of name (eg: bleh123.out), I need to have those filenames (just the filenames) printed out, one per line. How can that be done?

Thanks.

david_ross · 06-26-2003, 03:56 PM

Why not just use find?

brian0918 · 06-26-2003, 03:58 PM

Quote:

Originally posted by david_ross
Why not just use find?

But what would I use to have it only print the filenames?

if you use:

find . -name 'bleh*.*'

it prints out the directory structure.

david_ross · 06-26-2003, 04:01 PM

Use the print format:
find /path/to/smoewhere -name blah*.* -printf "%f\n"

brian0918 · 06-26-2003, 04:03 PM

Thanks.

brian0918 · 06-26-2003, 04:22 PM

Is there a way to have it only print everything up to the decimal point in the filename?
So if it finds bleh123.321, it prints out:

bleh123

david_ross · 06-26-2003, 04:44 PM

There is no print format to do that. The only way I can think of is to use awk. I'm not great with awk but this should work:

Code:

find /path/to/somewhere -name blah*.* -printf "%f\n" | awk -F. '{print $1}'

brian0918 · 06-26-2003, 04:48 PM

Quote:

Originally posted by david_ross
There is no print format to do that. The only way I can think of is to use awk. I'm not great with awk but this should work:

Code:

find /path/to/somewhere -name blah*.* -printf "%f\n" | awk -F. '{print $1}'

Thanks, it works.