Bash Script Returns Triple The Results Then It Would If Doing It Manually, Why?
 

Please review the following script and let me know what the issue is.

It will find files, however the output is triple Vs is I do it from the CLI, one at a time.

The above will output the files with the incorrect permissions only once.

thanks

Change:
to:
You're accidentally telling the find command to act on each the directories in first usage each time because you use original variable $DIRS. Your loop is designed to do a single directory on each iteration and that is what you are setting as $DIR.

Alternatively you could avoid the for loop altogehter by just doing:

Simple syntax error, thanks.

I still get confused on the for statement. The i is a variable and the other part if what we are looping thru, correct?

$DIRS is everything found where $DIR is each item in the list.

People often use "i" ($i) in for loops (i = iteration maybe?) but you can use any variable name you want. In yours you used DIRS for the list of directories then just DIR where others might have used i for each iteration. No reason not to use DIR ($DIR) instead of i ($i) other than typing. You could have used BILLYBOB ($BILLYBOB) and it would have worked so its all a matter of preferences.

I prefer to put names on variables because it gives me a clue later in long scripts what the variable relates to. I probably woulnd't have chosen DIRS and DIR given how close in name they are. I might have made first variable DIRLIST and the other DIR (or EACHDIR) to differentiate them but again its just a matter of preference. As shown, you can do what you want with DIRS and DIR.

I agree with MensaWater; always go out of your way to make the 'list' var and 'item' var names sufficiently different that you won't get stung like that :)
You'll thank us later ;)

As a general rule I almost never use just $i or equiv as loop vars any more.
For one thing you may have >1 loop in same file or set of files ...