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gregmcc

08-06-2013 06:16 AM

Bash script - grep in a loop

For some reason i am struggling with the following.

I have a command that greps out data from a text file:

Code:

cat file | grep Registration | awk '{print $3}'

This prints out:
10
11
22
32

I want to check if any of the values = 100 and then echo "Error"

I know I need to use a for loop but then how do I specify the number of times to loop, and if I put the grep in the loop wont it only spit out the first match each time?

druuna

08-06-2013 06:27 AM

Is this what you are looking for:

Code:

awk '/Registration/ { if ( $3 == "100" ) { print $3, "error" } else { print $3 } }' infile

Example run:

Code:

$ cat infile

Registration blaat 10

Registration foobar 11

Registration foo 100

Registration bar 22

Registration bar 32



$ awk '/Registration/ { if ( $3 == "100" ) { print $3, "error" } else { print $3 } }' infile 

10

11

100 error

22

32

gregmcc

08-06-2013 06:33 AM

Thanks a lot! Perfect!

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