Hey Folks,
I need to create a bash script that will launch 3 separate commands one after the other. I have decided to put in a sleep command between them so that it waits for a certain amount of time(since I am not 100% sure commands can be executed simultaneously or all at once). The output of command1 requires some time to process.So does the output of command2 and command3.

Do you consider this appropriate :

#!/bin/bash
cd /usr/sbin
command1(which performs analysis)
*here it asks for credentials*
Then it executes the command.

sleep (say 100 just in case )

command2(performs staging)
*here it asks for credentials*

sleep 100

command3(performs install)
*here again asks for creds*

Perhaps I can implement the username/pass as a variable.
VARIABLE1=username
VARIABLE2=password

Please let me know if you have any suggestions.

You are concerned about the processing ... do any of the commands require the other to complete prior to running or possibly interact with the same data so there could be a locking issue?

If not, then you should be able to launch each one in turn.

1 members found this post helpful.

Yes they should be launched in this order.Each command must complete before the other one is executed.Thats why I included the sleep.
Question is how do I define the variables for uname and pass and where in the script in particular?

Well as each relies on the previous I would probably use the && operator between each. This way only on successful completion of the previous command will the next execute.

As for setting variables, you could try looking into the expect command but of course it is inherently dangerous to have passwords in plain text form in a file.
So I would try and use something like sudo to elevate privileges of the user so passwords are not required.

But note that the system is asking for a uname/password which corresponds to another application.Root uname/pass just wont`do.Thats why I am concerned.

Then its back to investigating expect.