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I'm trying to write a bash script to find all lines containing two different strings in many files. I don't have access to egrep so I want to use sed for this purpose.
The files will look like this:
FileX
------
Info:18
Data:76
Contact:me@home.com
Start:1500
I want to generate a new file from these files with only the rows containing Data and Start. Something like this:
for y in `ls /file*.db`;
do sed '/Data|Start/p' $y > newfile
done
I'v tried to find a solution to this but not found it. Anyone have a suggestion for this?
Are you using the GNU version of sed? If so, you want "\|", rather than "|" as per the manual. Also, you probably want to use the -n option, to stop it printing out the entire pattern space.
Are you using the GNU version of sed? If so, you want "\|", rather than "|" as per the manual. Also, you probably want to use the -n option, to stop it printing out the entire pattern space.
The -r option tells sed to use extended regex, which supports operators such as "|", "+", and "()" without having to use backslashes.
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