LinuxQuestions.org - [SOLVED] Bash: if statement syntax

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Bash: if statement syntax

A simple test which doesn't work.

Code:

x=10

if [$x==10]

then echo hey

fi

The error message.

Code:

bash: [10==10]: command not found

Bash version.

Code:

bash-4.1$ bash --version

GNU bash, version 4.1.7(2)-release (i486-slackware-linux-gnu)

Copyright (C) 2009 Free Software Foundation, Inc.

License GPLv3+: GNU GPL version 3 or later <http://gnu.org/licenses/gpl.html>



This is free software; you are free to change and redistribute it.

There is NO WARRANTY, to the extent permitted by law.

Checked for syntax online which seems to suggest that I'm using the correct syntax. Bash syntax is annoying :( Help!

Nevermind found the solution myself.
if [$x==10] should be rewritten as if [ $x -eq 10 ]

Those spaces are important

Or when comparing numbers, use the construct designed to do so:

Code:

if (( x == 10 ))

Code:

x=10

if [ $x == 10 ]

then 

echo hey

fi

please note the spaces, "[" is also a command so you need to separate it from "if".
and run the script using
bash "scriptname"