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Old 08-10-2014, 04:57 PM   #1
mamunm
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bash for loop to copy files


I want to copy job-5, job-6, job-7..... to LA-1, LA-2 LA-3 ...
My command is : for subdir in LA-*; do (cd "$subdir"; cp -r /scratch/job-$(i+4) .); done But linux is not taking this command, can i do it in other ways? Thanks
 
Old 08-10-2014, 05:22 PM   #2
kbnuts
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well you've not defined a few things there. just putting LA-* doesn't invoke a filesystem command for starters so you'll need define it. I'm about to go to bed so can't give you a full answer but your first part will be more like:
for subdir in $(ls -l |awk '{print $9}' |grep LA); do...etc
Also you're pulling a command i+4 which doesn't make any sense in that context. If I had time I'd tell you the rest but my bed is calling me.
 
Old 08-10-2014, 10:54 PM   #3
mamunm
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I think my questions was not clear. I have folders named job-5 to job-7 and they are running in scratch directory. after the job is finished i want to copy them in folders named LA-1 to LA-4. Actually my main question was can i use $(i+4) for file name? If it was job-1 to job-4 and i had to copy them to LA-1 to LA-4, there was no problem, my above command can do that easily:for subdir in LA-*; do (cd "$subdir"; cp -r /scratch/job-$i .); done
 
Old 08-10-2014, 11:30 PM   #4
evo2
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Hi,

does the following do what you want?
Code:
for i in {1..9} ; do j=$((i+4)) ; echo cp -r /scrach/job-$j LA-$i; done
If not, please explain again. Perhaps write out the commands that you want run (for a single value of i), and we can show you how to automate it.

Cheers,

Evo2.

PS. Remove the "echo" to actually make it work.
 
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Old 08-10-2014, 11:35 PM   #5
mamunm
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Thanks, i think that would do the job. At first i tried two loops using i and j but than i realized that would be a mess. thanks for the idea.
 
Old 08-10-2014, 11:39 PM   #6
propofol
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How about:

Code:
cd scratch
for i in {1..3}; do echo "cp -r LA-$((i+4)) job-$i"; done
Remove echo & " " if it looks right.

Regards,
Stefan

Oops, Evo2 beat me to it.

Last edited by propofol; 08-10-2014 at 11:40 PM.
 
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