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Old 05-07-2009, 04:44 AM   #1
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awk one liner help

Hi and hello to all.

I am working on a very small script as a complete newbie and need a little help on an awk expression.

What I need to do:

I have a txt file whose first and only line is:

--username:someusername --password:somepassword --server:someserver

I am trying to extract the actual password so I can use as part of a sed routine so am storing the output to a variable.

--password is always in the same position in the file, but not at the same char count.

I have an awk one line which just uses the man examples so I can easily get the output to a variable of --password:somepassword by using $2, but all i need is the text string 'somepassword' which is the actual password text.

So, can anyone help with a one liner that can extract the password from this file and store as a variable?

Thank you.
Old 05-07-2009, 05:52 AM   #2
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Hi, welcome to LQ!

awk -F"[ :]" '{print $4}' file
should work. Untested, though, don't have awk here atm



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