awk find and replace

mmhs · 09-16-2013, 02:58 AM

hi guys

i have a simple question

i have a directory name like

"P1 ( 13 - 15 ) = 110"

how can i replace 13 and 15 with other variables
e.g i1=3 and i2=5

how can i replace 13 and 15 with $i1 and $i2

i use this code but that does not work

Code:

 
find . -type d -name "P*" |while read FILE
do
echo $FILE | awk '( $3 = "$i1"  ) { $5 = "$i2" } {print} ' 
.
.
.
done

shivaa · 09-16-2013, 03:29 AM

Can you try:

Code:

~$ echo "P1 ( 13 - 15 ) = 110" | awk '{gsub($3,"$i1",$3) && gsub($5,"$i2",$5); print $0}'

colucix · 09-16-2013, 05:14 AM

Please post your thread in only one forum. Posting a single thread in the most relevant forum will make it easier for members to help you and will keep the discussion in one place. This thread is being closed because it is a duplicate. Please, follow discussion here: http://www.linuxquestions.org/questi...er-4175477226/