awk ?

rhinoict · 01-11-2010, 09:06 AM

I have a .out file that has this information:
-rw-r--r-- 1 root system 1763444 Sep 30 18:11 log.td-ict-111

I just want a simple script to list only the last row of informatin (the log. names) How can I do this with awk?

TB0ne · 01-11-2010, 09:25 AM

Quote:

Originally Posted by rhinoict

I have a .out file that has this information:
-rw-r--r-- 1 root system 1763444 Sep 30 18:11 log.td-ict-111

I just want a simple script to list only the last row of informatin (the log. names) How can I do this with awk?

The man page for awk has all the options on it, and Google's got lots of examples, if you looked.

Awk, by default, splits things on white-space. So if you put your string into it, you want to print out field 9, based on your example.

Code:

awk '{print $9}'

SethsdadtheLinuxer · 01-11-2010, 09:37 AM

here's a nifty link
http://forums13.itrc.hp.com/service/...readId=1154641
the awk one-liner
awk 'END {print}' file
sed '$!d' file (- bonus)

cpplinux · 01-11-2010, 09:40 AM

NF means number of fields in awk. You can use $NF to refer to the last field.

Code:

awk '{print $NF}' myfile.out

Edit: Sorry, I thought you meant the last column. For the last row, go for SethsdadtheLinuxer's solution.

vrmartin2 · 01-11-2010, 10:46 AM

Just curious: Why use awk when you can use "tail -1 <file>"?

pixellany · 01-11-2010, 10:49 AM

Quote:

Originally Posted by vrmartin2

Just curious: Why use awk when you can use "tail -1 <file>"?

Almost certainly, because he/she meant columns and not rows.

rhinoict · 01-11-2010, 11:29 AM

pixellany was correct I was needing the last column of data from the .out file. The command that cpplinux suggested (awk '{print $NF}' myfile.out) worked perfectly in my applicaion.
Thanks to all for the help