hello!
My problem is, I have 2 jobs that were supsended with kill -19 ...

I want them to awake at 10 o clock in the evening...

How do I do this???

I tried several things out at 14:50 to see if it works:

at 14:52 < t

t is a file, where I wrote into bg %2,
because I want job 2 to awake in 2 min.
Nothing happend....


I tried to start this script from crontab...nothing happens here, too...

how the hell do I get this simple action running?

maybe try :

at 14.52 -f t

where t is your file ( according to " man at " )

egag

I tried that already, i also tried it by just typing at 14:52 .

at the prompt I typed my command

at>bg %2

and then enter and Ctrl-D

nothing happend though...

the same in the /etc/crontab file...i wrote instead of the file to be executet, the command I wished to have executed...

strange thing...

to add (maybe something important):

when I execude my script test, where the command bg %2 is written into, I get back following :

bash: bg: %2: no such job

maybe the variable %2 has to be ecaped?

I tried it also with \%2, but this doesn't seem to make a difference...

well... you first gotto make your script work ok,
why "%2" ; can't you just give in the name of the job ?

egag

i don't understand, it is a suspended job, what is the name of it? the name of the file that I have executed that started the indexing (my job)?
How can I identify the job, i mean that one which is marked with pid 1416 in my system.
When I make bg %2 in the shell, everything goes well..

here is the excerpt from what I retrieve when I type the "jobs"-command:

[1] - 1646 Stopped (signal) /usr/local/bin/htdig-dbgen (wd: /var/www/htdig/db)
[2] + 22394 Stopped (signal) ./htdig-dbgen (wd: /usr/local/bin)

which is the name of job 2??