hi all
i want to split a file using commandline argument
i have tried
split -l 2 filename


please give your suggestions
thanks in advance

Well where are you supposed to get the value from?

Dear assistance required,
why not use grep (assuming you have a phrase to use as a tag):
I created a text file with 54 lines (evenOdd.txt):
- every other line had the tag "even" or "odd"
- used the following on the command line to separate "even" and "odd" lines:
cat evenOdd.txt | grep -i even > evenOnly.txt (27 lines resulted - all with "even")
cat evenOdd.txt | grep -i odd > oddOnly.txt (27 lines resulted - all with "odd")
I know this is a fairly simple example, but you get the idea.
The split command assumes you want a certain number of lines regardless of the content.
Does this help?

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thanks guys
but when i execute my script
say ./abc.sh 1000 47 48
it must split the file

split the file HOW ??????
50/50 ?
first 1000 lines then the rest ?
or first 64 Bits of the file ,then the rest ( this is a bit common in binary image files) ?
even / odd lines ?
How ?

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First file having 2 records and last file having 5 and rest will have 1000 records each.

i have split the first and the last file i want to split the remaining files using command line arguments

what have you implemented so far?

while {
n=0
while IFS= read -r line && [ $(( n+=1 )) -le 100 ]
do
printf "%s\n" "$line"
done
split -l1000 - outfile
} < infile > outfilea0


but i want to split it using command line values

Bash command line substitutes from within the script are:

Try echo'ing this information:

And you can of course use the number of arguments as a loop limit value and perform tests:

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