Any arguement that can be used with 'ls' command to ignore case?

davidas · 04-13-2004, 06:44 AM

Some directories might have lots of files and some have names that contain capital letters. It would be useful to be able to list those directories without knowing which letter is in cap, hence the need for ignore case arguement for 'ls'.

Is there such an arguement to be used with 'ls' ?

Thanks

sims · 04-13-2004, 07:20 AM

Not quite sure what you mean, but I think grep will do what you ask for...

ls | grep -i dIRecToRY

davidas · 04-13-2004, 09:02 AM

Eg.

I have the following directories in my /myfolder directory:

subdiroNe
and ALOT more files in /myfolder

and I'm interested to (1) list the files in /myfolder/subdiroNe and to (2)check if subdiroNe directory exists. If I do a

Code:

ls subdiroNe

it will list the directory content if the directory exits (in this case it will list). But if I have forgotten that N is in caps, I would just done a

Code:

ls subdirone

which will return "The file or directory does not exist". So question is: Is there an arguement (aka grep's -i) that will allow ls to ignore case. ie.

Code:

ls -<some arguement> subdirone

and it will still list subdiroNe.

Thanks

Quote:

Originally posted by sims
Not quite sure what you mean, but I think grep will do what you ask for...

ls | grep -i dIRecToRY

sims · 04-13-2004, 09:34 AM

Sorry, don't think ls has this option. You could however do this:

Code:

ls `ls | grep -i subdirone`

The tab-completion comes in handy in these cases, of course.

jesus_edu · 04-13-2004, 10:34 AM

hello!
you can try so:
ls subdiro[nN]e
that will list subdirone or subdiroNe (or both, if there are there)

/bin/bash · 02-26-2006, 04:46 AM

Quote:

have the following directories in my /myfolder directory:

subdiroNe
and ALOT more files in /myfolder

and I'm interested to (1) list the files in /myfolder/subdiroNe and to (2)check if subdiroNe directory exists.

find /myfolder -iname subdirone