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Old 01-26-2005, 11:45 AM   #1
rafiqul
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Registered: Jan 2005
Location: Chicago
Distribution: Fedora Core 4
Posts: 46

Rep: Reputation: 15
access() function call does not work


I am supposed to verify a file accesibilty, whether it is readable, or writable..so i used access() system call. It is not working...

Here is my check...

#define FILE "./file.txt"

//I am changing the permission as r only
chmod (FILE, S_IRUSR | S_IRGRP | S_IRGRP)

//I am checking here if it is read, or write able
if(access(FILE, W_OK) == 0)
{
//file is wrioteable
} else if(access(FILE, R_OK) == 0)
{
//file is readable
}

I was expecting file is readable only...how come it is writeable ?

Any idea ??
 
Old 01-26-2005, 03:28 PM   #2
Disillusionist
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Registered: Aug 2004
Location: England
Distribution: Ubuntu
Posts: 1,039

Rep: Reputation: 97
A couple of things.

FILE is a data type used to declare file pointers, as such you should not use it as a macro

Next, ensure you include the correct library in your quote. I believe access is in the unistd.h library which was not included in the code supplied.

However I think your problem is that you are most likely running this code as root which supercedes the permissions on the file, so it always assumes a successful call to access, therefore it doesn't fall into the else if block of code.

BTW, this doesn't really belong in the Newbie forum.
 
  


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