9 partitions 2 are free
 

i have 9 partitions
C:Windows xp
D:Windows 2003
E:..............empty 7.70 Gb
F:Important data
G:Important data
H:Important data
I:Important data
J:Important data
K:..............empty 2.10 Gb

can someone tell me how to partition my drives to install linux without losing anything and keep the dual booting of xp and server 2003
and especially the part where i must mount all the drives i find it difficult after all i am a newbie

What distro do you want to install?

I suggest that you make "E" the root partition, and "K" the swap partition, which is all you really need install Linux. Note that drive letters is Windows terminology - Linux uses /dev/hda1 for the 1st partition on the 1st IDE hard drive, etc. Don't touch your other partitions, and you won't lose anything. Of course, make a backup in case of disaster.

Having said that, 7GB is not really enough for a fully functioning distro. I would strongly suggest that you get a new hard drive, and dedicate it to Linux.

Do you need to access your data in "F", - "J" in Linux? If so, are those partitions NTFS or FAT. You should realise that NTFS write support in Linux is not reliable.

When you install, most distros will detect both WinXP and W03, and setup the GRUB bootloader in the Master Boot Record for you. You will be able to select either of those or Linux when you boot your machine.

I hope this helps
--Ian

You did not say how big the drive is--or how full all the Windows partitions are. For example, if each partition is only 60-70% full, you may be wasting a LOT of space.
If you want to access all your data from Linux, then having all the data in FAT32 partition(s) is a common approach. You can also use ext2 or 3 and get a Windows tool to access that.
As already mentioned, just installing another drive may be the easiest way to go. Anything under 100GB is REALLY cheap.

Since you already have all that important data backed up, we won't mention that anymore....;)