'test' error

loopoo · 08-08-2005, 03:17 AM

Hi!

I have this lines in my script:

myvar=`dataload.sh $1 $2 $3 $log` ;

if test $myvar -eq 1
then
./script.sh
fi

and I get this error message:

./launch.sh: line 35: test: too many arguments

In 'dataload.sh', myvar appears twice:

myvar=0;

while ..
do
..
myvar=1 ;
done

and it is echoed at the end of the file to be recieved in the first script
echo $myvar;

What coud be wrong in my script?

Thanks in advance,
LooPoo

acid_kewpie · 08-08-2005, 04:18 AM

i'd guess that myvar is not a single digit. so...

1) echo out the value of myvar, inside this script before you test it. prove what's actually been recieved from the second script.

2) use [ ] notation instead of "test": if [ $myvar -eq 1 ] ... neater...

loopoo · 08-08-2005, 04:26 AM

thanks for your suggestion

I've already done that and I'm not recieving the right value, even though it a single digit (used as boolean - 0 or 1)

I'm searching the problem somewhere else now

heema · 08-08-2005, 07:00 AM

try putting double quotes around $myvar

Code:

if test "$myvar" -eq 1
then
./script.sh
fi