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- - ${0##*/} (https://www.linuxquestions.org/questions/linux-newbie-8/%24%7B0-%2A-%7D-4175495387/)

base=${0##*/}

can someone please explain this ?

Where did you get it from? To be honest, unless called in a script it is quite meaningless.

You may also like to read http://www.catb.org/~esr/faqs/smart-questions.html, as your current effort leaves little to be desired.

Same effect as

Code:

$(basename $0)

You're trimming everything to the left using '/' as a delimiter.

--C

anandg111, see the bash(1) manpages, under the "Parameter Expansion" section. There are a number of interesting features here, none of which require firing off a child process.

Some of my favorites:

Code:

[texas] ~> _line='Stay warm'



[texas] ~> echo "The length of \$_line is ${#_line}"

The length of $_line is 9



[texas] ~> echo "The first six characters from \$_line are ${_line:0:6}"

The first six characters from $_line are Stay w



[texas] ~> echo "Replacing (warm) with (happy) gives us: ${_line/warm/happy}"

Replacing (warm) with (happy) gives us: Stay happy



[texas] ~> echo "Greedily stripping prefix up to (a) results in: ${_line##*a}"

Greedily stripping prefix up to (a) results in: rm



[texas] ~> echo "Greedily stripping suffix up to (a) results in: ${_line%%a*}"

Greedily stripping suffix up to (a) results in: St

Anyway - read the manpages.

A really good page on Parameter Expansions & related tricks http://wiki.bash-hackers.org/syntax/pe