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Old 06-03-2017, 06:49 AM   #1
vincix
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opendns query


When I try to find out my public ip address, I sometimes run the following:
Code:
dig +short myip.opendns.com @resolver1.opendns.com

To be honest, though, I don't really understand how this works, exactly. First of all, if I query another dns server, it doesn't work. But I don't understand exactly the mechanism. Why shouldn't it work, after all? If I run @8.8.8.8 would it mean, theoretically, that the returned ip would be 8.8.8.8 instead of my public ip?
 
Old 06-03-2017, 12:12 PM   #2
bathory
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Quote:
Originally Posted by vincix View Post
When I try to find out my public ip address, I sometimes run the following:
Code:
dig +short myip.opendns.com @resolver1.opendns.com
To be honest, though, I don't really understand how this works, exactly. First of all, if I query another dns server, it doesn't work. But I don't understand exactly the mechanism. Why shouldn't it work, after all? If I run @8.8.8.8 would it mean, theoretically, that the returned imyip.opendns.comp would be 8.8.8.8 instead of my public ip?
What the command above does, is to query the opendns resolver for the IP of myip.opendns.com.

I guess myip is a special hostname (aliased maybe to a script), that makes opendns return the IP of the client issued the query. That's why it doesn't work using a different resolver.

Regards
 
  


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