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Linux Kernel source code: What does static void __##func mean?

Hello,
I am trying to find out what the CAL interrupt in /proc/interrupts is all about. I understand it's "Function Call interrupts" but there seems to be a dearth of information about what a Function Call interrupt really is. I can presume it means "an interrupt generated whenever you call a system call", but I'm not so sure about that. "Prove it," I says to myself.

So I did some digging and uncovered https://elixir.bootlin.com/linux/v5....nel/smp.c#L234 (assume we're staying in x86-land for now), which says

Code:

DEFINE_IDTENTRY_SYSVEC(sysvec_call_function)

{

        ack_APIC_irq();

        trace_call_function_entry(CALL_FUNCTION_VECTOR);

        inc_irq_stat(irq_call_count);

        generic_smp_call_function_interrupt();

        trace_call_function_exit(CALL_FUNCTION_VECTOR);

}

. This is where the CAL counter gets incremented (it's irq_call_count). Perfect!

But I can't figure out how DEFINE_IDTENTRY_SYSVEC(sysvec_call_function) is called. What is a "sysvec_call_function"? That's not defined anywhere. And DEFINE_IDTENTRY_SYSVEC has a definition that I don't understand:

Code:

#define DEFINE_IDTENTRY_SYSVEC(func)                                        \

static void __##func(struct pt_regs *regs);

...

(at https://elixir.bootlin.com/linux/v5....dtentry.h#L239)

I think I might understand better if I could figure out what

Code:

__##func

means.

Can you help? Thanks.

While I'm not sure about the details of what you're working on, it looks like that's a token concatenation. Macros in c are based on tokens, not pieces of text like it may at first appear.

Ex:

#define FOO(x, y) x##y
FOO(abc, def)

would be processed roughly as follows:

[FOO] ( [abc] , [def] )
[abc]##[def]
[abcdef]

The "##" acts to concatenate the two identifier tokens into a single identifier token. Essentially, the macro would turn something like:

DEFINE_IDTENTRY_SYSVEC(my_cool_function)

into:

static void [__my_cool_function] ( struct [pt_regs] * [regs] ) ;

instead of:

static void [__] [my_cool_function] ( struct [pt_regs] * [regs] ) ;

which would produce a compiler error.

Thanks. I understand, from your example, that the square brackets are not inserted by the macro preprocessor? In other words, technically it would be

static void __my_cool_function ( struct pt_regs *regs ) ;

and not

static void [__my_cool_function] ( struct [pt_regs] * [regs] ) ;

...Or do I misunderstand?

Yeah, sorry. I was using square brackets to show identifier tokens ([abc] was an identifier token named "abc").