Hi,

I am working on an embedded Linux project. In the project, I wish to get a GPIO interrupt in my user-space program. I read about using UIO to get kernel interrupt from user-space. However, it seems that I will have to do a blocking call, such as read(), poll(), to wait for interrupt happens. But I don't want to block and wait. Is there a solution would let my program act like a bare-metal project, where I attach an interrupt handler to the system and free to preform other tasks until an interrupt happens and the program jumps to the ISR?

Thanks,
Wei Xu

A hardware interrupt can't be trapped in user space, because any process could be running at the time the interrupt happens. A kernel-level handler must receive the interrupt, quash it, and then signal a user space program so that the program becomes runnable and will get notified.

Duplicate thread.

@sundialsvcs
Thanks for the reply. Could you provide some more details on how to 'signal' the user space program from the kernel?

Thanks,
Wei

Please post your thread in only one forum. Posting a single thread in the most relevant forum will make it easier for members to help you and will keep the discussion in one place. This thread is being closed because it is a duplicate.