LinuxQuestions.org - [SOLVED] Variables in text file, how to get their values when printing out the text?

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Variables in text file, how to get their values when printing out the text?

Hi!
I'm doing some bash-scripting and want to be able to print some text (just plain text) files into the new bash-scripts, created within a loop. Here's a short example of what I do:

Code:

############### main bash script ##################

#!/bin/bash 



##Filename

variable1=10



for ((j=0;j<=40;j+=1))

do

  ## Create another bash-script

  echo "#!/bin/bash" >> bash_script_$j

  ... some stuff...

  cat file1.txt >> bash_script_$j

  ... some more stuff...

done

where the text file (file1.txt) I want to print in the the new bash script looks something like:

Code:

############### file1.txt ##################

...some stuff...

logsave log some_program($variable1)

mv output_$j folder_$j/

... some more stuff...

I.e, the text file contains variables such as "$j", "$variable1" etc that are undefined. Doing the above works for creating new bash scripts (bash_script_1 - bash_script_40) but the variables are not determined. I would like, if possible, to somehow print the text in file1.txt into the new bash-scripts with the variables determined, i.e:

Code:

############### bash_script_1 ##################

...some stuff...

logsave log some_program(10)

mv output_1 folder_1/

... some more stuff...

The text files I read are quite extensive so I would really prefer not having to paste them into the FOR-loop directly. Does anyone have any suggestions? Thanks!
Ida

Presuming you call the scripts created on the fly, could you pass the variable values on the command line?

Code:

#!/bin/bash 



##Filename

variable1=10



for ((j=0;j<=40;j+=1))

do

  ## Create another bash-script

  echo "#!/bin/bash" >> bash_script_$j

  echo 'j=$1' >> bash_script_$j 

  ... some stuff...

  cat file1.txt >> bash_script_$j

  ... some more stuff...

  bash_script_$j $j

done

Alternatively, they could get the value of $j from their own name

Code:

j=${0##*_}

Hi!

I was able so solve the problem using the "sed" command:

Code:

sed -e s#'$variable1'#$variable1#g -e s#'$j'#$j#g file1.txt >> bash_script_$j

/Ida