GNU/linux 2.6, slackware 12.0

Hi:
I want to print, using locate, all the paths that contain the element /bin/ but only one instance of each one. If I issue 'locate /bin/' then I have many screens of text with, for example,
/usr/bin/foo1
/usr/bin/foo2
/home/me/bin/foo3
whereas I want to see only
/usr/bin/foo1
/home/bin/foo3

That is to say, if in two lines /bin/ appears with the same prefix (in the example above the prefixes would be /usr and /home/me) I only want to print the first line.

Can I pipe locate to grep to do this? I've mentioned locate because it does not scan the whole disk.
Thanks in advance.

Hi,

Not sure how to do this with locate (without multiple pipes), but find can.

find / -type d -name "bin"

This will also pick up the sbin directories, if those are not wanted/needed add: | grep -v "sbin"

Hope this helps.

1 members found this post helpful.

Unbelievable! It's a lot of time but I won't be doing this more than once. Thank you so much, druuna. Regards.

You're welcome

As stated, locate doesn't (atthe time) scan the disk - but locate also accepts regex. You an reduce the output mightily using that.

1 members found this post helpful.

Thank you, cyg00.