srcipt issue

Paxmaster · 03-29-2006, 01:13 PM

How can I make a srcipt that when a directory (/backup) have the size 45 GB or more it will run a other script

thanks

ckoniecny · 03-29-2006, 01:39 PM

Here is a untested script I just wrote, it should give you a general idea of where to start.

Code:

#!/bin/sh
SIZE=`df -k | grep backup | awk '{print $3}'`

if [ $SIZE -gt "45000000"]
then
     /usr/local/bin/morethan45gb.sh
else
     /usr/local/bin/lessthan45gb.sh
fi

The only bug in this script is if the volume uses 45000000k exactly, but you can figure that out if you want.

Paxmaster · 03-29-2006, 03:38 PM

I have edit the script to be more easy This is just a test

#!/bin/sh
$SIZE=`du -sh /home/paxmaster/Test/Music.tar | awk '{print $1}'`

if [ $SIZE= -gt "970" ]
then
/home/paxmaster/Test/remove
else
/home/paxmaster/Test/error

but I got an error

./script: line 2: =973M: command not found
./script: line 4: [: -gt: unary operator expected

ckoniecny · 03-29-2006, 04:22 PM

First,
Remove the $ sign from SIZE when using it as a variable at the top of your script (follow my example)
Secondly, look at my example, I dont have "= -gt", just "-gt".

Paxmaster · 03-29-2006, 04:34 PM

thanks it work