shell code help please
 

Hey,

2 questions regarding the shell.

1 - In a shell script i want several apps to run successively. ram1.pl, ram2.pl, ram3.pl etc. I've tried "./ram*" but that just ran the first script and stopped. Is there a way i can run these without typing them all out in the script?

2 - i want to get the output of 'time perl.pl' into a file. i tried 'time perl.pl > time.txt' but that didn't work. I tried echo `time perl.pl` > time.txt which also failed. I assume there is a way. Any help please?


Thanks

1)
for i in ram*
do
$i
done

2) the first way will work, unless it is being written to stderr instead of stdout. does changing > to 2> make a difference? If so, the code needs to be changed to use stdout properly.

1.

You asked for "successively". For simultaneous, do it this way:

2. The problem you were having with the second command arises from the fact that there are two "time" commands -- one a Bash builtin, the other a standalone with more features. This information comes to light by ... reading the manual.

Thanks guys. Very helpful.

try ./ram* &

that should work (i think!)

linux

Run the code

while ((flag != 1))
do
ram1.pl &
pid1=(ps -ef | grep ram1.pl | grep -v "grep")
ram2.pl &
pid2=(ps -ef | grep ram2.pl | grep -v "grep")
ram3.pl &
pid3=(ps -ef | grep ram3.pl | grep -v "grep")
ram4.pl &
pid4=(ps -ef | grep ram4.pl | grep -v "grep")
if [[ -z "$pid1" && -z "$pid2" && -z "$pid3" && -z "$pid4" ]];then
flag=1
fi
done