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The "-F ," portion in the second one tells awk to split on commas instead of on spaces, which is the default. You might have to run it through a couple of these filters to get rid of all of it.
If you wanted to print the second (or third, or whatever) item that is split by the token you have chosen (spaces, commas, whatever) just change the $1 to $2 or $3 or whatever number you want.
Are these two lists or are you showing to types of patterns from one list?
sed 's/ .*//' filename
sed 's/, .*//' filename2
Or if from the same list you can have two sed commands on one line:
sed 's/ .*//;s/, .*//' filename
Another form is the -e option:
sed -e 's/ .*//' -e 's/, .*//' filename
The "-F ," portion in the second one tells awk to split on commas instead of on spaces, which is the default. You might have to run it through a couple of these filters to get rid of all of it.
If you wanted to print the second (or third, or whatever) item that is split by the token you have chosen (spaces, commas, whatever) just change the $1 to $2 or $3 or whatever number you want.
If you indeed have the data the way you show it, it is easy:
For the "first" list---remove all after the " ":
sed -i 's/ .*//' filename (deletes everything from the first space to the end of the line the regex reads literally as "a space, followed by any number of characters")
A similar approach will work for the second case....
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