regular expression not working. grep[^0-9]
 

echo 8989898989898 |grep [^0-9] > /dev/null 2>&1
if [ "$?" -eq "0" ]
then
echo "inside if "
nrec=1
fi


output shows..

+ echo 8989898989898
+ grep 3
+ 1> /dev/null 2>& 1
+ [ 1 -eq 0 ]

Not sure how grep [^0-9] is converted to 3 . Any help.

You need to put the expression in quotes. It is being interpreted by the shell.

you can check it by:
echo [^0-9]