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Old 07-19-2005, 10:34 AM   #1
owix
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Registered: Jul 2005
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Process killing script


Hello everybody:

I am running a software which usually leaves undesired processes running after progam shutdown, always containing the directory where the binaries running are placed. I usually kill them by

> ps aux | grep my-
owix 28346 0.0 0.6 72608 6788 ? S 17:24 0:00 /work/my-release/my_dir/installed/i686-slc3-gcc323-opt/bin/rc_empty_controller
owix 28347 0.0 0.6 93220 6948 ? S 17:24 0:00 /work/my-release/my_dir/installed/i686-slc3-gcc323-opt/bin/rc_empty_controller -n RootController
owix 28575 0.0 0.0 4772 680 pts/5 S 17:27 0:00 grep my-

and then:

> kill -9 28347 28346

Then I would like to have an script which kill all the processes belonging to a specific user (owix) and that contains in the description the "my-release" pattern.
Do you have any idea about how to do this? Thanks you very much. Cheers,

OWIX
 
Old 07-19-2005, 11:04 AM   #2
hamish
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Registered: Aug 2003
Location: Edinburgh
Distribution: Server: Gentoo2004; Desktop: Ubuntu
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ps aux | grep my-owix > tempfile

then use awk to select the first colum from that temp file. Can't quite remember the code, but it iwll be something like:

awk '{ print $1 }' tempfile > temp2

then write a script to get the PID from temp2.

hamish
 
Old 07-19-2005, 11:08 AM   #3
demian
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Registered: Apr 2001
Location: Bremen, Germany
Distribution: Debian
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ps aux|grep owix|grep [m]y-release|awk '{print $2}'|xargs kill -9

Last edited by demian; 07-19-2005 at 11:09 AM.
 
  


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