problem with sort in linux and sed

labelle7152 · 12-22-2005, 10:54 AM

sirclif

Quote:

860610103 3113958944966740579012759994359105 14740192326 2194235 99712868 82 0 0 0 107675 1 570 12421111123A
860610103 4 83907765675740579011994593814105 10116725553 2044235 99782901 66 0 0 0 107639 1 710 12421111123A
860610103 5121162529333740579012651927211764 19127780178 2274235 99812906

I used this piece of data to help explain
the date starts as number 8 03 is the year 3 is the third day of Jauruary and 1139589944966 is the
seconds in hundreds of a seconds starting from 1201 am.
the Julian calander numbers the days in the year from 1-365 so Jan 1st is 1 Feb 1st is 29 ect
the day are right jusified by blanks so in these three lines you have 3 for Jan3rd 4 for Jan 4th
and 5 for Jan 5th dose that help

Tinkster · 12-22-2005, 11:37 AM

Try

Code:

sort -u -g -t @  -k1.8,1.9 -k1.10,1.12n -k1.13,1.130 -o ajisai_e10.0301 ajisai_e.0301

Hoping that I got that 130 right as the total length of your
input lines :}

Cheers,
Tink

P.S.: I still find it hard to believe that the original sort
in Unix would have made sense of those lines... it only would/
could if someone had modified the ASCII table on that particular
machine so that space comes directly before 0.

labelle7152 · 12-23-2005, 09:27 AM

Tinkser
Thanks It worked. You are a life saver. The user disk had failed on the older Unix based computer
we were using (The system manager stop backing up the old system and did not save any old backup !!)
so I had to get this working on the Linux computer.

sirclif
thanks for all the help

Tinkster · 12-23-2005, 11:14 AM

That'll be a 5 dollar donation to gnu.org or LQ please ;}

Cheers,
Tink