Parse out only specific characters from web page
 

Hi. I am using curl to download a specific web page, basically I need the CustName: from the query run on whois.domaintools.com

If you type an ip address, it will return the organization name. I need only this information saved in a plain text file. I tried using grep -E but it gets messy because there are many &nbsp and ;&nbsp located after the CustName. Also the string is returned in one long line so grepping for CustName returns that same long line. The characters that follow the information I need are simply a new line which is '<br>'. I need to stop grabbing text up until that point.

So what I do is run

Then I run

The 120 stands for characters after CustName. Much of these are &nbsp and ;nbsp. I use 120 to make sure I grab everything. Basically, since the data is all in one line, they use <br> right after the information I need. The Address section is below CustName and that is not what I need. I would only like the information up until the <br>

Here is an example of the output of the above command:

As you can see, the only information I want is Akamai Technologies. How can I parse out this data in the most efficient way? Thank you for any help.

If you 'elinks -dump' then you have parsed output to grep or awk? Or else pipe the curl through a parser like http://www.devshed.com/c/a/apache/logging-in-apache/2/ (see "Listing 3-1. A Simple Script to Use As a Filter")?

Hi. I'm not sure what parser means here. I saved the output of the curl command to a file and just ran grep from there. Sorry new to parsing in apache.

Perhaps I'm missing something here, but why not use "whois"?

The problem is that whois does not seem to work with every ip address