Need to separate the following value 'xxx.xxx.xxx.xxx:xx:xx'

SlowCoder · 09-14-2007, 03:32 PM

I'm sure sed or awk will come into play here. But I can't figure 'em out!

I need to split a line of text, based on the first instance of colon ":".

For instance, if I have the line 'xxx.xxx.xxx.xxx:yy:zz' I want a return of both the left ('xxx.xxx.xxx.xxx'), and the right ('yy:zz').

Any help?

wjevans_7d1@yahoo.co · 09-14-2007, 04:05 PM

What language are you using? What did you try so far, and what happened?

anomie · 09-14-2007, 04:09 PM

One idea:

Code:

[mrbig]$ var=($(echo 'xxx.xxx.xxx.xxx:yy:zz' | sed 's/:/ /'))

[mrbig]$ echo ${var[0]}
xxx.xxx.xxx.xxx

[mrbig]$ echo ${var[1]}
yy:zz

carl0ski · 09-14-2007, 04:19 PM

another

Code:

var1=($(echo 'xxx.xxx.xxx.xxx:yy:zz' | cut -d ':' -f 1))
echo $var1

xxx.xxx.xxx.xxx

Code:

var2=($(echo 'xxx.xxx.xxx.xxx:yy:zz' | cut -d ':' -f 2,3))
echo $var2