is that possible?

marsguy · 04-12-2006, 11:57 AM

Hello

My question is quite long but I think the answer will be quite simple:

I have a directory called "enigma", That "enigma" directory contains several text files, you can say that those text files are resumes which off course contain "name" ana "age" of some people.

what I want to do is grep 2 fields which are: "name" and "age".

And then put the result in one file so it may look something like this

Mark 25
John 29
Emilia 23

is it possible to this using only shell commands, I am not familiar with writing scripts yet.

Thanks

kaz2100 · 04-12-2006, 12:19 PM

If you can describe what you want to do, yes, it is possible.
If not, no.

geeman2.0 · 04-12-2006, 12:22 PM

That's going to depend highly on the format of these resumes.
Your typical resume could have the name just about anywhere, which would make it pretty hard to find it automatically.

marsguy · 04-12-2006, 12:39 PM

Thanks for the fast replies:

All the files in the "enigma" directory looke like this:

Name : Name
Age : 32
Gender : Male
Home Address : Liberity avenue
phone : 1234567

Thanks again

kaz2100 · 04-12-2006, 01:12 PM

Code:

grep 'Age\|Name' yourFile

will give you

Code:

 Name : Name
Age : 32

Then 'cut' 'tr'.... and several other utilities will give you desired format.
Using 'perl' may be easier.

marsguy · 04-12-2006, 03:55 PM

kaz2100, Thank you very much

you are great

timmeke · 04-13-2006, 02:00 AM

I agree that Perl might be ideal for this.

But you can also try something like this:

Code:

for i in `ls resumes`; do
   age=`grep Age $i|cut -d' ' -f3`;
   name=`grep Name $i|cut -d' ' -f3`;
   echo "$name $age";
done

This should work, as long as the format is:
Name<space>:<space>some_name
Age<space>:<space>some_age

Of course, you'll need to change the ls command in the for-loop to give you a list
of the files that contain the "resumes".