LinuxQuestions.org - how to log out from all instances of unix?

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how to log out from all instances of unix?

i have log in to my unix home directory through telnet from windows machine.
While working with vi editor, suddenly it stopped responding to any keystroke. So i have closed the telnet window by clicking on "X" on top right corner. so that window got closed but the instance of unix is still alive.
So next time i have log in to unix through telnet. Now i have typed the command 'who' and it shows me two instances of the same user. One is previous and second is that i have just log in. Now if i want to log out from both the instances of unix then how can i do it? Because whenever i typed 'exit' or cntrl D it will exit from current instance but that previous is always alive.
Please help me as early as possible.

First you type

Code:

w

to list the users logged in. Observe the column "TTY". Remember the values printed there for each instance you want to log out. Next, execute

Code:

ps aux

This also has a column "TTY". Find the process ids (columnt "PID") of the instances you want to kill. Next, you can kill them by typing

Code:

kill 123

Code:

kill -9 123

where 123 is an example process id, which should be replaced with the correct ones.

Note that the missing session is harmless and will eventually (after one minute or so) go away by itself, so the above exercise is pretty much useless.

Groetjes,

Kees-Jan