In case anyone else is interested, I did find a solution to my question, so I thought I would post it. It turns out you can use the "filefrag" command to find the physical location of a file:
Code:
filefrag -v myfile.txt
It gives an output like:
Code:
Checking myfile.txt
Filesystem type is: ef53
Filesystem cylinder groups is approximately 115
Blocksize of file myfile.txt is 4096
File size of myfile.txt is 121460 (30 blocks)
First block: 2209841
Last block: 2212769
Discontinuity: Block 7 is at 2211636 (was 2209847)
Discontinuity: Block 11 is at 2211645 (was 2211639)
Discontinuity: Block 13 is at 2211925 (was 2211647)
Discontinuity: Block 14 is at 2211931 (was 2211925)
Discontinuity: Block 19 is at 2211966 (was 2211935)
Discontinuity: Block 26 is at 2212669 (was 2211972)
Discontinuity: Block 29 is at 2212769 (was 2212671)
myfile.txt: 8 extents found, perfection would be 1 extent
4096 * 2209841 = 9,051,508,736, so that means the file starts about 9 GB into the partition.