How to execute multiple commands with find and -exec...
 

I see several references to the ability to execute multiple commands on the results of a single find command.

What I am trying to do is use a flag to track which files have been processed by a recurring script.

I find the files that do NOT have the flag set, then I process them. Next I want to set the flag.

Problem is that the list of files returned by the flag will be different because time elapses between the first and second incidence of the find commands.

So, what I want to do is use a single list to execute both commands.

Anyone have a single line solution that does NOT involve writing a script, or a solution that involves storing the results of the find in a temporary file?

Thanks

Tom


EG:
find ./ -flags noopaque -exec chmod a+x
fins ./ -flags noopaque -exec chflags opaque

repeat every 10 minutes

Note - this is an example only - these are not the exact commands I am running...

find ./ -flags noopaque -exec cmd1 -exec cmd2

painfully simple huh?

Why not put it in a crontab?
10 * * * * * find ./ -flags noopaque |xargs chmod a+x && chflags opaque 2>&1 >/dev/null

Ouch
 

OUCH!

Thanks!

Does not work with Solaris 10:

find . -name "Batch*.txt" -exec cat {} -exec echo "============" \;
...
cat: cannot open -exec
cat: cannot open echo
cat: cannot open ============

I really would appreciate any help! :)

Each -exec action must terminate with an escaped semi-colon, otherwise all the rest of the line is interpreted as the command to execute.

Thanks! This is it!