how to escape variable in bash???
 

Hi. I want to be able to see if bash can escape a variable. The
variable will be *dynammically generated* so I can't just manually put
in slashes. It will be running mysql command and capturing the
output. Example Like this:


#!/bin/bash
VAR = `mysql -u "user" -B -N -e "SELECT auth FROM table WHERE user='xxxx' " db --password="password"`;

echo $VAR; # need it to be escape the "."and "@"

can this be done in bash????

Can you post the output of the above command, I dont understand what you are trying to achieve.

Cheers :)

Cyber

I am trying to use that returned data and filter it through procmail. Procmail requires data with periods, and @ signs to be escaped. Example of output is from the above query via bash:

@ymdomain.com|info@mysite.com|customersupport@nospam.com|orders@yahoo.net|billing@youcare.net

I want to be able manipulate that data using bash and plug into procmail to filter it as either authorized emails or blocked emails....

Use sed to replace the '@'s with '/@'s and the '.'s with '/.'s, like so:

var = `echo $var | sed s/@/\\/@/g | sed s/\\./\\/\\./g`

Ian

Of course!!! I totally forgot about sed! I use it for other things, but forgot about the application here. Thanks!!