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Old 09-01-2008, 03:36 AM   #1
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Cool How can i sort the "w" output by IDLE time?

Hi all,

I have 100's of sessions on my Linux server and I want to kill off sessions that have been IDLE for a long time.

I can see the IDLE time of the sessions by using the w command, but I wanted to know if there was a way I can sort the output of the w command by IDLE time, starting with the highest IDLE time going down to the lowest?

Any help would be MUCH appreciated
Old 09-01-2008, 03:40 AM   #2
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w |sort -n -k 5
Old 09-01-2008, 03:58 AM   #3
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Thanks for that matthewg42, that was driving me CRAZY!!

Old 09-01-2008, 07:23 AM   #4
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See this you might find it useful.

=>Print users who are idle for more than 15 mins
who -u | sed -e "s/\./0/" -e "s/://g" | awk '$6 > 15' | awk '{print $7}'
=>Kill the above users.
kill -9 `who -u | sed -e "s/\./0/" -e "s/://g" | awk '$6 > 15' | awk '{print $7}'`

Add below code /etc/bashrc
export TMOUT=300
case `tty | cut -d "/" -f 3` in
   tty1|tty2|tty3|tty4|tty5|tty6 ) export TMOUT=300;;
So that shell sessions on the consoles 1-6 are logged out after 5 mins idle time, but those running withing a GUI session such as Gnome or KDE or over an ssh connection are not affected.

Hope this helps.
Old 09-10-2008, 03:40 AM   #5
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Talking Brilliant

Hey vikas027,

Sorry for the late reply, I have been away, but thanks for your suggestion, it works perfect.



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