grep files

graziano1968 · 11-05-2012, 04:49 AM

Hello

I need to search in a folder /usr/local/app/data/
all files names which
have the word "house" inside the file
AND and which
does NOT have the word "car" inside the file.

Is it possible to do that with a single command (possibly using egrep , not sure if also sed could help) ?

Thank you

colucix · 11-05-2012, 04:55 AM

If you mean the word "house" or "car" in the file name (not inside the files) you can try the find command:

Code:

find /usr/local/app/data -name \*house\* ! -name \*car\*

pixellany · 11-05-2012, 05:05 AM

Code:

ls /usr/local/app/data | sed -n '/house/{/car/!p}'

I don't think you can do it with a single GREP command

graziano1968 · 11-05-2012, 05:08 AM

Quote:

Originally Posted by colucix

If you mean the word "house" or "car" in the file name (not inside the files) you can try the find command:

Code:

find /usr/local/app/data -name \*house\* ! -name \*car\*

No I mean text inside the file , not text inside the file name.

syg00 · 11-05-2012, 05:20 AM

I've seen some mighty contortions trying to use the wrong tool - usually because of some inane requirement. Teachers seem to be enamoured of such.

Use awk or perl.

graziano1968 · 11-05-2012, 05:30 AM

Quote:

Originally Posted by syg00

I've seen some mighty contortions trying to use the wrong tool - usually because of some inane requirement. Teachers seem to be enamoured of such.

Use awk or perl.

I could do this using php , however I was asking if there is an easy/fast way to do that using a single command line , as it seems no.

colucix · 11-05-2012, 05:45 AM

Not a single command, but a simple command line:

Code:

grep -lr house /usr/local/app/data/* | xargs grep -L car

graziano1968 · 11-05-2012, 06:06 AM

Quote:

Originally Posted by colucix

Not a single command, but a simple command line:

Code:

grep -lr house /usr/local/app/data/* | xargs grep -L car

Thank you