grab the line below a blank line and the line above the next blank line awk or perl?
 

Hello,

I am trying to grab the full line below a blank line and the full line above the next blank line, group them together and throw a blank line inbetween them and the next entry like that in the output.

There might also be an easier way, I am trying to get the folder size and the last access time of that folder to make an audit.

Any help would be appreciated. Thanks!

How about showing us the real command output you are trying to parse, and how you want it to look. I'm pretty confused with your description.

ditto ... Please give example

as I understand it OP wants:
turned into:

That may very well be, but the issue is one of forcing a method of implementation based upon the OPs current perception of how to obtain an answer to a given problem.

A better method would be to describe the goal more precisely (eg. "how do I get total folder size and last access time of a file in a folder?") rather than focusing on the implementation ("how to I solve some problem using some tool I'm not sure is the right tool").

If I am correct in what the user is asking, this is not the best or easiest approach. But I'll wait the OP to clarify.

I think the OP wants 'du --time'.
This will give the directory size and time of last modification of a file in a directory.

I finagled a way to get the output I desired. It wasn't the most elegant approach. I wanted

{BLANK}
qwerty
rtuygfvbfgh
jhgfghjrtyg
12345
{BLANK}
67890
44444
88888
{blank}

turned into

{blank}
qwerty
12345
{blank}
67890
88888
{blank}

basicly just take the first and last lines in a block of text and group them together.

There may be a way to stop grep printing '--' between matched contexts, but I couldn't find it, hence the second grep.