[SOLVED] find and kill all zombie processes

mahmoodn · 08-04-2011, 04:01 AM

I want to find all zombie processes and kill them. from http://www.cyberciti.biz/tips/killin...e-process.html I know that

Code:

ps aux | awk '{ print $8 " " $2 }' | grep -w Z

will find the zombie processes but it will show like

Code:

Z 4104

. How can I kill all of them?

syg00 · 08-04-2011, 04:09 AM

Why don't you read the complete article ?.

kirukan · 08-04-2011, 04:19 AM

Quote:

print $8 " " $2

From "ps aux" output $8, $2 print 8th and 2nd fields

unSpawn · 08-04-2011, 04:26 AM

...in addition to post #1: killing zombies is fighting symptoms not addressing the cause, which is what you should do.

mahmoodn · 08-04-2011, 04:36 AM

I tried this

Code:

ps aux | awk '{ print $8 " " $2 }' | grep -w Z | awk '{ print $2 }' | xargs -0 sudo  kill -9

That will first print
"Z 11022"
and then
"11022"
Then I used xargs to pass a command to each output. Is this correct?

Code:

xargs -0 sudo  kill -9

However I get this output:

Code:

...
11022
".
Usage:
  kill pid ...              Send SIGTERM to every process listed.
  kill signal pid ...       Send a signal to every process listed.
  kill -s signal pid ...    Send a signal to every process listed.
  kill -l                   List all signal names.
  kill -L                   List all signal names in a nice table.
  kill -l signal            Convert between signal numbers and names.

wladimirec · 08-31-2011, 02:32 AM

I've got the same problem and found handy info here:
LinuxQuestions.org > Forums > Linux Forums > Linux - General : [SOLVED] Cleaning up this kill command
http://www.linuxquestions.org/questi...ommand-892571/

it should looks like:

Code:

for pid in $(ps aux | awk '{ print $8 " " $2 }' | grep -w Z | awk '{ print $2 }'); do kill -9 $pid; done;