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Old 01-28-2004, 07:43 AM   #1
chrisk5527
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Figuring out download speed


Lets say I'm downloading at 768k. Why do I have to divide 768/8? I realize there are 8 bits in a byte, but why do I have to? Dont really understand.
 
Old 01-28-2004, 08:26 AM   #2
kevinatkins
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hi,

it's really a matter of most filesizes being quoted in kilobytes, wheres modem transfer rates etc are quoted in kilobits / second. so, if you have a 56k modem, to get the transfer rate in kilobytes / second, you need to divide 56 by 8 (=7!). then to get the time required to download, say, a 1MB file, simply divide 1024 (1MB = 1024kB) by 7, which gives a result in seconds.

note that a dial-up modem will not connect at 56k, maximum is around 53k i believe.

here's a useful link -

http://www.allwindows.com/modemtimes.html
 
Old 01-28-2004, 08:35 AM   #3
chrisk5527
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I have a broadband connection connected at 768k. I know I can download at 768/8=98kbps. I guess my question wasnt clear enough. How come when you have do divide the connect speed by 8 to arrive that the download speed? Why is the 8 so significant?
 
  


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