Hello.
I have been trying to find a way to pipe the following to a file within a script that does this for each entry in an input file. However, obviously the carrots do not work with echo:

<echo 'img src="$i.jpg" caption="$i" link="http://kozybabies.com/shopping.htm" />' >> test.xml

This command work in the script, and I am adding the carrots using an external file (kind of barbaric):

echo 'img src="'$i.jpg'" caption="'$i'" link="http://test.zone/test.htm"' >> test.xml

Does anyone know a way to pipe the original command out keeping the carrots in place..?

Thanks,
Lou

Maybe I need to eat more carrots because I don't see any carets (^) in your message.

I really don't know which character you are referring to. Enter "help echo" or "man echo" for options such as -e which would allow you to use certain escape sequences which can include a character of the form \0nnn. Also look at escaping the character you don't want the shell to handle. A variable, like $i needs to be in double quotes if you need to expand it.

Your second line looks OK except for missing the beginning and closing tags.

Also look at using a here document to construct a html page.

You could construct the top of the page in a here document, iterate through the arguments in a loop, and then finish the documents with another here document.

The info bash manual has information about HERE documents.

Another option is to use the "printf" command instead of echo.

Sorry for the confusion, I was working off very little sleep when I wrote out the original post.

What I needed to do is pipe this line from my script into an output file. The problem is that echo removes the quotes in the process.

However, the printf command worked perfectly, thanks much for the info.

printf '<img src="'$i.jpg'" caption="'$i'" link="'http://zome.com/shopping.htm'" />\n' >>out /r >> $WHOME/images.xml

Regards,
Lou

perhaps this should also work: