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I'm writing a script that relaunches itself with root permissions. It starts like this:
#!/bin/sh
CMDLN_ARGS="$@"
if [ $UID -ne 0 ]; then
echo 'Please enter root password'
echo su root -c "$0 $CMDLN_ARGS"
echo su root -c "$0 $@"
exec su root -c "$0 $CMDLN_ARGS"
fi
In this case, it works fine. However, if I replace $CMDLN_ARGS in the exec line with $@, it breaks for multiple input arguments. But the echo statements tell me that both lines should be identical. What gives? I can get my script to work, but I'd really like to understand the issue here.
Thanks. But assuming I want the script to handle it gracefully, instead of the user modifying his input? I've tried quoting my input \"$@\" in script but it doesn't work.
#!/bin/bash
CMDLN_ARGS=("$@")
if [[ $UID -ne 0 ]]; then
echo 'Please enter root password'
echo su root -c "$0" "${CMDLN_ARGS[@]}"
echo su root -c "$0" "$@"
exec su root -c "$0" "${CMDLN_ARGS[@]}"
fi
Location: Bangalore ,Karnataka, India, Asia, Earth, Solar system, milky way galaxy, black hole
Distribution: murugesan openssl
Posts: 181
Rep:
Updated code using $@:
Using ksh (USEksh.sh)
Code:
#!/bin/ksh
CMDLN_ARGS="$@"
if [[ $UID -ne 0 ]]; then
echo -n 'Please enter root password'
echo su root -c "$0" "${CMDLN_ARGS[@]}"
echo su root -c "$0" "$@"
exec su root -c "$0 $@"
else
echo You cab execute: $@ : if required
#$@
fi
Using bash(USEbash.sh)
Code:
#!/bin/bash
CMDLN_ARGS="$@"
if [[ $UID -ne 0 ]]; then
echo -n 'Please enter root password'
echo su root -c "$0" "${CMDLN_ARGS[@]}"
echo su root -c "$0" "$@"
exec su root -c "$0 $@"
else
echo You cab execute: $@ : if required
#$@
fi
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