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Old 01-23-2013, 01:50 PM   #1
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Registered: Jan 2013
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BASH scripting Condition Statements

Hello, my code looks as follows:

if [ "$state" = 1 ] && [ "$i" = *1* ] && [ "$i" != *Batch* ] && [ "$i" != *Int* ]; then 

   echo "--------------------------------"
However it yells at me because I have more then 2 conditions.

Is there a way to force it to accept 4-6 conditions?

Old 01-23-2013, 02:18 PM   #2
Registered: Oct 2011
Location: New Zealand
Distribution: Debian
Posts: 105

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Originally Posted by Xyaib View Post
if [ "$state" = 1 ] && [ "$i" = *1* ] && [ "$i" != *Batch* ] && [ "$i" != *Int* ]; then 
   echo "--------------------------------"
I see two problems here. First, you have used "=" (used for variable assignment) when you need to use "==" (used for equality in a test statement). Second, bash has a preferred double-bracket syntax for test-conditions - it allows you to move the "&&" inside, as described here.
if [[ "$state" == 1  && "$i" == *1* && "$i" != *Batch* && "$i" != *Int* ]] ; then
   echo "--------------------------------"
Happy with ur solution... then tick "yes" and mark as Solved!

Last edited by dru8274; 01-23-2013 at 02:45 PM.


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