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Bash : add cr to stdout

Hi,
Maybe it is a simple question for you guys but I a newby in bash script programming...
Here it is :

When in a script I do a

Code:

z=$(ls -al 2>&1)

echo $z

var=$?

the output for z give the good result but with no new line or carriage return.

Is there a simple way to output the result of the command and display it with carriage return for each new line?
By the way, I want to retrieve stdrr so that's why I am using 2>&1 and var=$?.

Thanks

Two things:
- The answer is: surround your $(...) construct with double quotes.
- The return status stored in var is that of the echo command. You probably want to have the var= line just under the ls -al line; however, I'm not sure you'll get the return status of ls -al as this command is burried in a subshell...

Yves.

Quote:

Originally Posted by theYinYeti (Post 2875792)

Thanks for replying me!
Well I have tested your solution but that's not seems to work...
Ok, here is the code

Code:

        z="$(ls -al 2>&1)"

        var=$?

        echo $z

The output is :

Code:

total 12 drwxr-x--- 2 romain romain 4096 Aug 30 11:22 . drwx------ 10 romain romain 4096 Aug 30 11:22 .. -rwxr-x--- 1 romain romain 1303 Aug 30 11:22 test.sh

What I want is :

Code:

total 12

drwxr-x---  2 romain romain 4096 Aug 30 11:22 .

drwx------  10 romain romain 4096 Aug 30 11:22 ..

-rwxr-x---  1 romain romain 1303 Aug 30 11:22 test.sh

As you can see, the output of ls does not add any carriage return or new line code..

I will check for the stderr stuff later.

Thanks

Yes I forgot that you ALSO have to put double quotes around the variable name as an argument to echo, which gives:

Code:

z="$(ls -al 2>&1)"

var=$?

echo "$z"

Yves.

SOLVED : Bash : add cr to stdout

Perfect! That's working.
By the way, I have tested the stderr code and it seems to catch successfully the error code (0 or 1) when the ls function is executed.