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Old 05-17-2005, 02:58 PM   #1
Registered: Jun 2004
Distribution: Turtle Kevux 0.8.8
Posts: 129

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hacking agetty for lfs

Okay, I find myself starting to recode much of the nicely done no longer maintained software for my lfs distro.

In the past I remember having agetty hang at load login time after logging on, and I am relatively fast on the console, so I get:
login: me

where mypasswo was the password I'm typing in.

Now, I believe there is a way to stop sending text to the output, if I can find this linux command I can fix it so that no password is printed to the screen once user name is typed in.

My problem is I am not sure which source package to look into to find agetty. I am pretty sure its one of the core packages....any help?
Old 05-19-2005, 02:14 PM   #2
LQ Newbie
Registered: Jan 2004
Location: Germany
Distribution: MyGeOs
Posts: 6

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Old 05-20-2005, 03:43 PM   #3
Registered: Jun 2004
Distribution: Turtle Kevux 0.8.8
Posts: 129

Original Poster
Rep: Reputation: 15
thanks I'll get right to it
Old 05-23-2005, 05:49 AM   #4
LQ Newbie
Registered: Nov 2004
Location: Bucarest, Romania
Distribution: My own
Posts: 26

Rep: Reputation: 15
there is a C++ command to stop echo... after you type your username you stop echo, and after you type a password you rechange the line caracteristics.

In fact, you ask for something stange: init calls fork, then the child calls getty, that shows the message "login:"

After you type the username, getty calls something like
execle ("/usr/bin/login", "login" "-p" , username, (char *) 0, envp)

then login program use the argv[3] to see what the username is, etc...

So I think that the solution is difficult, and not sure to exists, only if the system has a buffer to remember the string you typed to the keyboard between getty gives the control to login, and login gives the prompt for the password.

Sorry if I have made grammar mistakes.


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