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Well, I am currently a sophmore in high school and I truly think that math is pointless. I am so strong about that oppinion that I came up with a theorem that shows that all numbers are equal therefore proving math is retarted.
Check out my formula and tell me if it mathmatically correct, I am still amazed I figured out how to do this.
Code:
a + b = t
(a + b)(a - b) = t(a - b)
a^2 - b^2 = ta - tb
a^2 - ta = b^2 - tb
a^2 - ta + (t^2)/4 = b^2 - tb + (t^2)/4
(a - t/2)^2 = (b - t/2)^2
a - t/2 = b - t/2
a = b
Theorem: All numbers are equal.
Proof: Choose arbitrary a and b, and let t = a + b. Then
So all numbers are the same, and math is pointless.
I've seen this stuff a long time ago, written in a slightly different form. The error, as far as I remember is here:
Quote:
(a - t/2)^2 = (b - t/2)^2
a - t/2 = b - t/2
You cannot assume directly that, if x^2=y^2, then x=y, simply eliminating the square operand. This happens because of the possible existence of negative solutions to the equation. This can be easily seen if we write
Code:
(-2)^2=(+2)^2=4, but
(-2)!=(+2)
So math does have some point, like it or not (not that I would like it).
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