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Old 09-15-2005, 12:25 PM   #1
Iriel
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Registered: Sep 2003
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Distribution: Fedora Core 4, Knoppix, openSUSE 10
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finding empty directories with bash


At work, we hired a consultant to help us with our shopping cart software (because the tmp files were never getting cleaned out). His solution was handing us a shell script that would do it for us. The only problem is that it's not working on Solaris 9. I think Solaris 9 doesn't support the -empty option, but I'm not sure. Could anyone help me fix this script?

Code:
/usr/bin/bash
/usr/local/somedirectory/bin/expireall -r
rm -rf /usr/serverdirectory/tmp/addr_ctr/*
find /usr/serverdirectory/tmp -type f -mtime +2 |xargs rm -f
find /usr/serverdirectory/tmp -type d -empty -depth -mindepth 1 |xargs rmdir
 
Old 09-15-2005, 01:05 PM   #2
druuna
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Hi,

You are correct, the -empty option is not supported.

I do have a solution, although it's kinda 'dirty'.....

Replace this line:
find /usr/serverdirectory/tmp -type d -empty -depth -mindepth 1 |xargs rmdir

With:
find /usr/serverdirectory/tmp -depth -type d -exec rmdir {} 2>/dev/null \;

It searches for all directories and tries to remove them using rmdir. rmdir will refuse to remove dirs that are not empty. Check to see if there isn't an alias defined that overrides this!!! (man rmdir for details).

The 2>/dev/null is there to get rid of all the error messages rmdir produces on non-empty dirs.

If at all possible, try this on a test box first.

Like I said, not elegant, but it works.
 
Old 09-15-2005, 01:52 PM   #3
jlliagre
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A cleaner approach would be to use the find command for which the original script was written, aka gnufind or gfind, which is certainly available for Solaris, at least on blastwave.
 
  


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