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Old 10-21-2005, 07:04 AM   #1
bob_man_uk
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logging off by script or finding PID of session


Hi all,

nice and easy question for you,
i have a menu based script with various options last one on the list is exit (as you do) but it exits to the shell which i dont want, i want it to exit and log off, if there is no easy command for that then how do i find the PID of the current session to kill it?

thanks in advance

MattyG
 
Old 10-21-2005, 08:07 AM   #2
unSpawn
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Current session is "$$" in Bash.
 
Old 10-21-2005, 08:35 AM   #3
bob_man_uk
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"$$" doesnt give me a propper PID (or the one for my session at least)

who -um gives me what i need now i just need to work out how to get my script to pull the PID from the list

cheers

MattyG
 
Old 10-21-2005, 06:58 PM   #4
unSpawn
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FWIW, Bash has builtin "logout".
 
Old 10-23-2005, 08:24 AM   #5
bob_man_uk
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just to let you know the logoff/logout/exit commands dont work from inside the script,

user logs in and this script comes up as soon as they log in, what i want is when they press q the script ends and the whole session logs off! should i post the script maybe im looking in the wrong area
 
Old 10-25-2005, 08:43 PM   #6
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If you "exec" this script from their shells ~/.bash_login then it should work, right?

should i post the script maybe im looking in the wrong area
If all fails that could help. Rip out parts we don't need to see so we keep focus.
 
Old 10-27-2005, 03:37 AM   #7
bob_man_uk
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ok i vorrowed the script from here

http://sunsite.uakom.sk/sunworldonli...7-unix101.html

scroll down to

Listing 1: Sample shell script menu

the layout is pretty much the same except i have sub'd in options for programs i want to run instead of what it shows on the site

Quote:
If you "exec" this script from their shells ~/.bash_login then it should work, right?
i dont understand can you explain a little please
 
  


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