1) I want to delete all files which have extention out from specific folder.
Which command I can use?
Following files which I want to delete in one command
456.out
987.out
876.out
----
-----

2) I want to delete the files older then specific date from a folder?



Thanks in Advance
Sajjad

hi,


to delete use the rm command...

for exmple :

rm -f *.out,


this will delete all the files with .out at the end without asking (-f option = force) if you have folders you whant to delete, use the -r option. ()recursive)

for more information use the manual (man rm)

i hope i could help you

leg

what about
2) I want to delete the files older then specific date from a folder?

when I use the said command
rm -f *.out,
the following error message dispaly

[oracle@visiondb1 PROD_proddb]$ rm -f *.out
bash: /bin/rm: Argument list too long

To delete multiple files you need to use a wildcard, which is the * character. (Yes, it's your asterisk.) * means every possible string of numbers and letters, including spaces.

Examples:

Delete all files in a directory:

rm *

Be very, very careful with this. If I want to delete everything in the /usr/bin/foo directory, I type:

rm /usr/bin/foo/*

Thus specifiying the directory. (It's unnecessary and paranoid, but I do it anyway, because I might one day want to type "rm -RF," which removes all files and all subdirectories, and I want to keep the good, safe habit.)


To delete all files starting with the word "star" type:

rm star*

This will remove starfish, star.doc, star.conf.bak, star.html, etc.


To delete all files that end in out, type

rm *.out.

Keep the period. Make sure you don't type

rm *out

because that will also remove shout, pout, standout, etc.

Also, type

man rm

so you can learn about the "rm" command.

You can also use the * with commands such as cp, ls, etc.

I can't help you with removing things after a certain date. You'll have to write a script and I don't have time to fiddle with that tonight.

To do it manually, you'll need to type

ls -algFs

which will give you a listing of all files with dates. You can probably do something like

ls -algFs | grep 2003

or

ls -algFs | grep "Jan 7"

and get a list of old files.

Alex

argument too long???

*) uh, this is new for me... maybe in your system there are another options for rm... i'm using FC2. try without the -f option, of loock in the manual for the "force" option.


*) you whant do delete files olther than "Date", for that i don't know a program.
but what you can do is to sort the files by date
ls -lt, or ls -c1t (to have only the files name)

you could use something like this to make a textfile with the output of ls:

ls -c1 -t > sort-list

now do a ls -lt and compare and delete the lines of "sort-list", where newer files are.

run: rm `cat sort-list`

bye

leg

Hi Alex
I have used the command rm *.out. but the following error display

[oracle@visiondb1 PROD_proddb]$ rm *.out.
rm: cannot remove `*.out.': No such file or directory

can you please tell me the exact command to remove files with extion out.

thanks

Take out the period. You typed:

rm *.out.

Instead, type:

rm *.out


Alex

hi Alex
when I type said command
rm *.out
the following error message dispaly

[oracle@visiondb1 PROD_proddb]$ rm *.out
bash: /bin/rm: Argument list too long
[oracle@visiondb1 PROD_proddb]$

thanks

try this:

for i in *.out ; do rm $i ; done

I don't understand, please type the exact command

I just made some files with .out extensions and tried to remove them. The command

rm *.out

worked perfectly. This makes me think that someone aliased the rm command to something silly. Try typing

alias

at the command prompt. This will show you a list of aliased commands. You may discover that "rm" has been connected to an incorrect command. Commands such as "rm" or "cp" that can affect files in a dangerous manner are usually aliased with the "-i" extension, so if you see output like this:

alias rm="rm -i"

then you're ok. If "rm" is not on the list you need to look elsewhere for the problem. On the other hand, if you see something that looks like this:

alias rm="rm -i -t -N"

then rm has been aliased improperly. In this case you should type:

alias rm="rm -i"

which will give you a sane "rm" command. Then try:

rm *.out

The other possibility is that you're working on a drive which someone else has mounted and on which you don't have proper permissions. This can cause some commands to behave erratically. In fact, I just got an identical error message (Argument list too long) trying to eject a CDROM drive as "alex" which I had mounted as "root."

You may have to su to root, or contact your sysadmin.

Alex

the command is:
for i in *.out ; do rm $i ; done

type it on a xterm or konsole (and in the right location, where your files are placed)

Hi Alex
Thanks for your quick support
I am log in with user root and try the alias and rm command. alias command shows the right result which u have mentioned but the rm command display same error message. the result of two commands are as

[root@visiondb1 PROD_proddb]# alias
alias cp='cp -i'
alias l.='ls -d .[a-zA-Z]* --color=tty'
alias ll='ls -l --color=tty'
alias ls='ls --color=tty'
alias mv='mv -i'
alias rm='rm -i'
alias which='alias | /usr/bin/which --tty-only --read-alias --show-do
lde'
[root@visiondb1 PROD_proddb]# rm *.out
bash: /bin/rm: Argument list too long
[root@visiondb1 PROD_proddb]#

thanks

hi
the command is:
for i in *.out ; do rm $i ; done
this command run sccussfully, but it prompt on every file before deletion. I want to delete all files with out extention without prompting.
[root@visiondb1 PROD_proddb]# for i in *.out ; do rm $i ; don
rm: remove `o165278.out'? y
rm: remove `o165291.out'? y
rm: remove `o165296.out'? y
rm: remove `o165301.out'?


thanks